X+((x+2)/4)=22

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Solution for X+((x+2)/4)=22 equation: 



X+((X+2)/4)=22

We move all terms to the left:

X+((X+2)/4)-(22)=0

We multiply all the terms by the denominator


X*4)+((X+2)-22*4)=0

We add all the numbers together, and all the variables

X*4)+((X+2)=0

Wy multiply elements

4X^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{8}=0$

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