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X*3X=600
We move all terms to the left:
X*3X-(600)=0
Wy multiply elements
3X^2-600=0
a = 3; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·3·(-600)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{2}}{2*3}=\frac{0-60\sqrt{2}}{6} =-\frac{60\sqrt{2}}{6} =-10\sqrt{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{2}}{2*3}=\frac{0+60\sqrt{2}}{6} =\frac{60\sqrt{2}}{6} =10\sqrt{2} $
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