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X(X-5)=-12+2X
We move all terms to the left:
X(X-5)-(-12+2X)=0
We add all the numbers together, and all the variables
X(X-5)-(2X-12)=0
We multiply parentheses
X^2-5X-(2X-12)=0
We get rid of parentheses
X^2-5X-2X+12=0
We add all the numbers together, and all the variables
X^2-7X+12=0
a = 1; b = -7; c = +12;
Δ = b2-4ac
Δ = -72-4·1·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*1}=\frac{6}{2} =3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*1}=\frac{8}{2} =4 $
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