If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X(X-11)=840
We move all terms to the left:
X(X-11)-(840)=0
We multiply parentheses
X^2-11X-840=0
a = 1; b = -11; c = -840;
Δ = b2-4ac
Δ = -112-4·1·(-840)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-59}{2*1}=\frac{-48}{2} =-24 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+59}{2*1}=\frac{70}{2} =35 $
| 7(y-3)=2(y+7) | | 4x-3÷5-3x=-2 | | 2b/3+5=20-b | | 5=0.73q+1.35 | | (8/3)c-2=(2c/3)-12 | | b=(9,0.40,7) | | 0.2x+5/0.3x-3=2/5 | | 5x=11(x+3)+7 | | b=(8,0.35,5 | | 3m+7=5m-3 | | 5x+3=7x+6=9 | | 15x+8=-1x+8x | | y8-3/5=y6-10/8 | | -73-9n=9+8n | | x-3/5=4x-9/18 | | (4x-5)/(3x-5)=3/2 | | -6-7v=8v+74 | | 7,25x-3=35,26x+9,86 | | 11x-3=4x+15 | | 25x(x−4)=4(1−25x) | | 15(y*y)+8=-14y | | 5(x+3)=3x−4 | | 10+4x=2x+30 | | 26x=25/2x+27 | | 2x+37=9x-5 | | 2x+28/8=5 | | 2x+29/5=7 | | 9x-8=18x+6 | | 7x+9x=450 | | 12w-7+9w=10+12w+3 | | 5/6-40/x=0 | | 2.3x^2+x^2=80 |