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X(X+8)-(106)=0
We multiply parentheses
X^2+8X-106=0
a = 1; b = 8; c = -106;
Δ = b2-4ac
Δ = 82-4·1·(-106)
Δ = 488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{488}=\sqrt{4*122}=\sqrt{4}*\sqrt{122}=2\sqrt{122}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{122}}{2*1}=\frac{-8-2\sqrt{122}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{122}}{2*1}=\frac{-8+2\sqrt{122}}{2} $
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