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X(X+7)=(X+3)(X+2)
We move all terms to the left:
X(X+7)-((X+3)(X+2))=0
We multiply parentheses
X^2+7X-((X+3)(X+2))=0
We multiply parentheses ..
X^2-((+X^2+2X+3X+6))+7X=0
We calculate terms in parentheses: -((+X^2+2X+3X+6)), so:We add all the numbers together, and all the variables
(+X^2+2X+3X+6)
We get rid of parentheses
X^2+2X+3X+6
We add all the numbers together, and all the variables
X^2+5X+6
Back to the equation:
-(X^2+5X+6)
X^2+7X-(X^2+5X+6)=0
We get rid of parentheses
X^2-X^2+7X-5X-6=0
We add all the numbers together, and all the variables
2X-6=0
We move all terms containing X to the left, all other terms to the right
2X=6
X=6/2
X=3
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