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X(X+65)=315
We move all terms to the left:
X(X+65)-(315)=0
We multiply parentheses
X^2+65X-315=0
a = 1; b = 65; c = -315;
Δ = b2-4ac
Δ = 652-4·1·(-315)
Δ = 5485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{5485}}{2*1}=\frac{-65-\sqrt{5485}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{5485}}{2*1}=\frac{-65+\sqrt{5485}}{2} $
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