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X(X+3)=560
We move all terms to the left:
X(X+3)-(560)=0
We multiply parentheses
X^2+3X-560=0
a = 1; b = 3; c = -560;
Δ = b2-4ac
Δ = 32-4·1·(-560)
Δ = 2249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2249}}{2*1}=\frac{-3-\sqrt{2249}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2249}}{2*1}=\frac{-3+\sqrt{2249}}{2} $
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