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X(X+23)=2X(2X+7)
We move all terms to the left:
X(X+23)-(2X(2X+7))=0
We multiply parentheses
X^2+23X-(2X(2X+7))=0
We calculate terms in parentheses: -(2X(2X+7)), so:We get rid of parentheses
2X(2X+7)
We multiply parentheses
4X^2+14X
Back to the equation:
-(4X^2+14X)
X^2-4X^2+23X-14X=0
We add all the numbers together, and all the variables
-3X^2+9X=0
a = -3; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-3)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-3}=\frac{-18}{-6} =+3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-3}=\frac{0}{-6} =0 $
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