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X(X+1)=510
We move all terms to the left:
X(X+1)-(510)=0
We multiply parentheses
X^2+X-510=0
a = 1; b = 1; c = -510;
Δ = b2-4ac
Δ = 12-4·1·(-510)
Δ = 2041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2041}}{2*1}=\frac{-1-\sqrt{2041}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2041}}{2*1}=\frac{-1+\sqrt{2041}}{2} $
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