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X(7X+45)=28
We move all terms to the left:
X(7X+45)-(28)=0
We multiply parentheses
7X^2+45X-28=0
a = 7; b = 45; c = -28;
Δ = b2-4ac
Δ = 452-4·7·(-28)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-53}{2*7}=\frac{-98}{14} =-7 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+53}{2*7}=\frac{8}{14} =4/7 $
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