X(5x-7)=(5x+4)(x-3)

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Solution for X(5x-7)=(5x+4)(x-3) equation: 



X(5X-7)=(5X+4)(X-3)

We move all terms to the left:

X(5X-7)-((5X+4)(X-3))=0

We multiply parentheses

5X^2-7X-((5X+4)(X-3))=0

We multiply parentheses ..

5X^2-((+5X^2-15X+4X-12))-7X=0



We calculate terms in parentheses: -((+5X^2-15X+4X-12)), so:

(+5X^2-15X+4X-12)

We get rid of parentheses

5X^2-15X+4X-12

We add all the numbers together, and all the variables

5X^2-11X-12

Back to the equation:

-(5X^2-11X-12)



We add all the numbers together, and all the variables

5X^2-7X-(5X^2-11X-12)=0

We get rid of parentheses

5X^2-5X^2-7X+11X+12=0

We add all the numbers together, and all the variables

4X+12=0

We move all terms containing X to the left, all other terms to the right

4X=-12

X=-12/4

X=-3

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