X(5x-4)=(5x+7)(x-2)

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Solution for X(5x-4)=(5x+7)(x-2) equation:



X(5X-4)=(5X+7)(X-2)
We move all terms to the left:
X(5X-4)-((5X+7)(X-2))=0
We multiply parentheses
5X^2-4X-((5X+7)(X-2))=0
We multiply parentheses ..
5X^2-((+5X^2-10X+7X-14))-4X=0
We calculate terms in parentheses: -((+5X^2-10X+7X-14)), so:
(+5X^2-10X+7X-14)
We get rid of parentheses
5X^2-10X+7X-14
We add all the numbers together, and all the variables
5X^2-3X-14
Back to the equation:
-(5X^2-3X-14)
We add all the numbers together, and all the variables
5X^2-4X-(5X^2-3X-14)=0
We get rid of parentheses
5X^2-5X^2-4X+3X+14=0
We add all the numbers together, and all the variables
-1X+14=0
We move all terms containing X to the left, all other terms to the right
-X=-14
X=-14/-1
X=+14

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