If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2*x^2-(8*x)+6 > 0
tan(x)*cos(9*x^2)
(x+1)/3-((y+2)/4)-((2*(x-y))/5);(x-3)/4-((y-3)/3)+x-(2*y)
y-(32*x)-315.8;y-(11.4*x)-325.6
8*(X/4) = 2
| 8n+8=12n | | g(x)=0.1x-0.3 | | 79t+24=119t | | 3=g/4–1 | | -2.2x=1.6 | | 7(8+5x)=336 | | h=16t^2+900 | | 5.5n=n+27 | | 51=5b+7-9b | | -4-16x=0 | | 2(3x-4)=-14 | | -7k+19=9k+18 | | 950r+10500=1475r | | 14=2g+8 | | -4-16=0 | | -3-4m=29 | | 19x+1.50=15x+2.27 | | (x+30)+(5x-25)+(4x)=180 | | 2y-8x=62 | | y=-x^4+6x^3-9x^2 | | 8-4x=y | | x+40+x-44=180 | | f(x)=x^4-x^2-90 | | 5x-2(2x+5)=-12 | | R+17.1=-4.8 | | 4j+7=2j-17 | | F(x)=-x^4+6x^3-9x^2 | | 10x+4x+3+7=4x+3+9x | | 8y-55=y | | (7x+3)+(2x-3)=180 | | 12x+9=9x+4 | | (4x+5)(3x+4)=0 |