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X(4X-4)=120
We move all terms to the left:
X(4X-4)-(120)=0
We multiply parentheses
4X^2-4X-120=0
a = 4; b = -4; c = -120;
Δ = b2-4ac
Δ = -42-4·4·(-120)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*4}=\frac{-40}{8} =-5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*4}=\frac{48}{8} =6 $
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