X(3x-9)=(3x+4)(x-5)

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Solution for X(3x-9)=(3x+4)(x-5) equation: 



X(3X-9)=(3X+4)(X-5)

We move all terms to the left:

X(3X-9)-((3X+4)(X-5))=0

We multiply parentheses

3X^2-9X-((3X+4)(X-5))=0

We multiply parentheses ..

3X^2-((+3X^2-15X+4X-20))-9X=0



We calculate terms in parentheses: -((+3X^2-15X+4X-20)), so:

(+3X^2-15X+4X-20)

We get rid of parentheses

3X^2-15X+4X-20

We add all the numbers together, and all the variables

3X^2-11X-20

Back to the equation:

-(3X^2-11X-20)



We add all the numbers together, and all the variables

3X^2-9X-(3X^2-11X-20)=0

We get rid of parentheses

3X^2-3X^2-9X+11X+20=0

We add all the numbers together, and all the variables

2X+20=0

We move all terms containing X to the left, all other terms to the right

2X=-20

X=-20/2

X=-10

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