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X(3X-8)=24
We move all terms to the left:
X(3X-8)-(24)=0
We multiply parentheses
3X^2-8X-24=0
a = 3; b = -8; c = -24;
Δ = b2-4ac
Δ = -82-4·3·(-24)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{22}}{2*3}=\frac{8-4\sqrt{22}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{22}}{2*3}=\frac{8+4\sqrt{22}}{6} $
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