If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X(3X+5)-50=0
We multiply parentheses
3X^2+5X-50=0
a = 3; b = 5; c = -50;
Δ = b2-4ac
Δ = 52-4·3·(-50)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*3}=\frac{-30}{6} =-5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*3}=\frac{20}{6} =3+1/3 $
| (3x-6/6)=3 | | 3x-6/6=3 | | 2x-13=-3x/5 | | 1-5x+1=6x | | 5t-18=4t | | 6(x-2)=(3x+4) | | 3s+2=2s−5 | | 3y-5-y=11 | | 3(3x+18)=13 | | 6+4x/3+x+9/6=17 | | b-2.25=4.46 | | 2x+3=4x−1 | | 7-x+3+2x=13 | | 3(x+16)=56 | | 2x+14/x=16 | | i-3=11(1-3) | | 2x+14/x=2 | | 42/4=x | | 56=5x+3 | | -3(2t+3)=-33t | | -2u+10=22 | | 4(x)=42 | | 4+x=42 | | 6=z/3-2 | | 10(s-8)=-133 | | 4(3s+4)=148 | | 5a-11=3a-2 | | x+144x=180 | | X+6/9=x-13/6 | | -2=x-6x-6 | | 5x−29=15−6x | | 2(7x+4)=9(x-3) |