X(3x+2)=800

Solution for X(3x+2)=800 equation:

X(3X+2)=800

We move all terms to the left:

X(3X+2)-(800)=0

We multiply parentheses

3X^2+2X-800=0

a = 3; b = 2; c = -800;
Δ = b2-4ac
Δ = 22-4·3·(-800)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-98}{2*3}=\frac{-100}{6}
=-16+2/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+98}{2*3}=\frac{96}{6}
=16
$