X(3x+2)=3(x2-4)

Solution for X(3x+2)=3(x2-4) equation:

X(3X+2)=3(X2-4)

We move all terms to the left:

X(3X+2)-(3(X2-4))=0

We add all the numbers together, and all the variables

-(3(+X^2-4))+X(3X+2)=0

We multiply parentheses

-(3(+X^2-4))+3X^2+2X=0


We calculate terms in parentheses: -(3(+X^2-4)), so:

3(+X^2-4)

We multiply parentheses

3X^2-12

Back to the equation:

-(3X^2-12)


We add all the numbers together, and all the variables

3X^2+2X-(3X^2-12)=0

We get rid of parentheses

3X^2-3X^2+2X+12=0

We add all the numbers together, and all the variables

2X+12=0

We move all terms containing X to the left, all other terms to the right

2X=-12

X=-12/2

X=-6