X(3x+10)=3000

Solution for X(3x+10)=3000 equation:

X(3X+10)=3000

We move all terms to the left:

X(3X+10)-(3000)=0

We multiply parentheses

3X^2+10X-3000=0

a = 3; b = 10; c = -3000;
Δ = b2-4ac
Δ = 102-4·3·(-3000)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36100}=190$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-190}{2*3}=\frac{-200}{6}
=-33+1/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+190}{2*3}=\frac{180}{6}
=30
$