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X(3+6X)=5
We move all terms to the left:
X(3+6X)-(5)=0
We add all the numbers together, and all the variables
X(6X+3)-5=0
We multiply parentheses
6X^2+3X-5=0
a = 6; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·6·(-5)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129}}{2*6}=\frac{-3-\sqrt{129}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129}}{2*6}=\frac{-3+\sqrt{129}}{12} $
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