X(2x-4)+x(2x-3)=(4x+2)(X-3)

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Solution for X(2x-4)+x(2x-3)=(4x+2)(X-3) equation: 



X(2X-4)+X(2X-3)=(4X+2)(X-3)

We move all terms to the left:

X(2X-4)+X(2X-3)-((4X+2)(X-3))=0

We multiply parentheses

2X^2+2X^2-4X-3X-((4X+2)(X-3))=0

We multiply parentheses ..

2X^2+2X^2-((+4X^2-12X+2X-6))-4X-3X=0



We calculate terms in parentheses: -((+4X^2-12X+2X-6)), so:

(+4X^2-12X+2X-6)

We get rid of parentheses

4X^2-12X+2X-6

We add all the numbers together, and all the variables

4X^2-10X-6

Back to the equation:

-(4X^2-10X-6)



We add all the numbers together, and all the variables

4X^2-7X-(4X^2-10X-6)=0

We get rid of parentheses

4X^2-4X^2-7X+10X+6=0

We add all the numbers together, and all the variables

3X+6=0

We move all terms containing X to the left, all other terms to the right

3X=-6

X=-6/3

X=-2

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