X(2x-3)=2x(x-4)+10

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Solution for X(2x-3)=2x(x-4)+10 equation: 



X(2X-3)=2X(X-4)+10

We move all terms to the left:

X(2X-3)-(2X(X-4)+10)=0

We multiply parentheses

2X^2-3X-(2X(X-4)+10)=0



We calculate terms in parentheses: -(2X(X-4)+10), so:

2X(X-4)+10

We multiply parentheses

2X^2-8X+10

Back to the equation:

-(2X^2-8X+10)



We get rid of parentheses

2X^2-2X^2-3X+8X-10=0

We add all the numbers together, and all the variables

5X-10=0

We move all terms containing X to the left, all other terms to the right

5X=10

X=10/5

X=2

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