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X(2X-20)=-13
We move all terms to the left:
X(2X-20)-(-13)=0
We add all the numbers together, and all the variables
X(2X-20)+13=0
We multiply parentheses
2X^2-20X+13=0
a = 2; b = -20; c = +13;
Δ = b2-4ac
Δ = -202-4·2·13
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{74}}{2*2}=\frac{20-2\sqrt{74}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{74}}{2*2}=\frac{20+2\sqrt{74}}{4} $
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