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X(2X-12)+30=180
We move all terms to the left:
X(2X-12)+30-(180)=0
We add all the numbers together, and all the variables
X(2X-12)-150=0
We multiply parentheses
2X^2-12X-150=0
a = 2; b = -12; c = -150;
Δ = b2-4ac
Δ = -122-4·2·(-150)
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8\sqrt{21}}{2*2}=\frac{12-8\sqrt{21}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8\sqrt{21}}{2*2}=\frac{12+8\sqrt{21}}{4} $
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