X(2x+x)=124

Solution for X(2x+x)=124 equation:

X(2X+X)=124

We move all terms to the left:

X(2X+X)-(124)=0

We add all the numbers together, and all the variables

X(+3X)-124=0

We multiply parentheses

3X^2-124=0

a = 3; b = 0; c = -124;
Δ = b2-4ac
Δ = 02-4·3·(-124)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{93}}{2*3}=\frac{0-4\sqrt{93}}{6}
=-\frac{4\sqrt{93}}{6}
=-\frac{2\sqrt{93}}{3}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{93}}{2*3}=\frac{0+4\sqrt{93}}{6}
=\frac{4\sqrt{93}}{6}
=\frac{2\sqrt{93}}{3}
$