X(2x+4)=2x(x-3)-80

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Solution for X(2x+4)=2x(x-3)-80 equation: 



X(2X+4)=2X(X-3)-80

We move all terms to the left:

X(2X+4)-(2X(X-3)-80)=0

We multiply parentheses

2X^2+4X-(2X(X-3)-80)=0



We calculate terms in parentheses: -(2X(X-3)-80), so:

2X(X-3)-80

We multiply parentheses

2X^2-6X-80

Back to the equation:

-(2X^2-6X-80)



We get rid of parentheses

2X^2-2X^2+4X+6X+80=0

We add all the numbers together, and all the variables

10X+80=0

We move all terms containing X to the left, all other terms to the right

10X=-80

X=-80/10

X=-8

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