X(2x+1)=(x-3)(x+5)

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Solution for X(2x+1)=(x-3)(x+5) equation: 



X(2X+1)=(X-3)(X+5)

We move all terms to the left:

X(2X+1)-((X-3)(X+5))=0

We multiply parentheses

2X^2+X-((X-3)(X+5))=0

We multiply parentheses ..

2X^2-((+X^2+5X-3X-15))+X=0



We calculate terms in parentheses: -((+X^2+5X-3X-15)), so:

(+X^2+5X-3X-15)

We get rid of parentheses

X^2+5X-3X-15

We add all the numbers together, and all the variables

X^2+2X-15

Back to the equation:

-(X^2+2X-15)



We add all the numbers together, and all the variables

2X^2+X-(X^2+2X-15)=0

We get rid of parentheses

2X^2-X^2+X-2X+15=0

We add all the numbers together, and all the variables

X^2-1X+15=0

a = 1; b = -1; c = +15;
Δ = b2-4ac
Δ = -12-4·1·15
Δ = -59
Delta is less than zero, so there is no solution for the equation

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