If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X(10X+30)=0
We multiply parentheses
10X^2+30X=0
a = 10; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·10·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*10}=\frac{-60}{20} =-3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*10}=\frac{0}{20} =0 $
| 6(x-12)=(-60) | | 15h-9=(-54) | | (-15)=5x+2x-1 | | 5n+3=2(2+2)-3n | | 25=80−11x | | (4t+3)/5=(t+3)/2 | | 8+9c=(-10) | | 12x/3=18 | | 9=4x–11 | | 41−2x=9 | | 2000/3x+50=5.50 | | 10+3x-12=-2+38 | | -3x+19=-14 | | 9+8x=9x-9 | | 1/3=7/y | | 3x+4=(-8) | | Y(2+3y)4=5 | | 7g-6=(-20) | | 130+40x=170+x | | (x+18)2=5x | | y^-6=42 | | 2-x=-3(x+4)=6 | | 10x+5=450 | | (a+5)(a+3)=80 | | (X-5)+2y+y=100 | | -21=21+8y | | (2a-5)=(3a+1) | | f=16/3×12+13/10 | | (4x+1)2+9(4x+1)=−18 | | 3(d-3)=5(1.5+d) | | 15-x=2(2x+3) | | 47.1=2(3,14r) |