X^2+30x=225

Solution for X^2+30x=225 equation:

X^2+30X=225

We move all terms to the left:

X^2+30X-(225)=0

a = 1; b = 30; c = -225;
Δ = b2-4ac
Δ = 302-4·1·(-225)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30\sqrt{2}}{2*1}=\frac{-30-30\sqrt{2}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30\sqrt{2}}{2*1}=\frac{-30+30\sqrt{2}}{2}
$