X^2+10x=133

Solution for X^2+10x=133 equation:

X^2+10X=133

We move all terms to the left:

X^2+10X-(133)=0

a = 1; b = 10; c = -133;
Δ = b2-4ac
Δ = 102-4·1·(-133)
Δ = 632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{632}=\sqrt{4*158}=\sqrt{4}*\sqrt{158}=2\sqrt{158}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{158}}{2*1}=\frac{-10-2\sqrt{158}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{158}}{2*1}=\frac{-10+2\sqrt{158}}{2}
$