V5x(V6x-4)=-2x

Solution for V5x(V6x-4)=-2x equation:

5V(6V-4)=-2V

We move all terms to the left:

5V(6V-4)-(-2V)=0

We multiply parentheses

30V^2-20V-(-2V)=0

We get rid of parentheses

30V^2-20V+2V=0

We add all the numbers together, and all the variables

30V^2-18V=0

a = 30; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·30·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*30}=\frac{0}{60}
=0
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*30}=\frac{36}{60}
=3/5
$