V(x)=(11+-2x)(17+-2x)

Solution for V(x)=(11+-2x)(17+-2x) equation:

(V)=(11+-2V)(17+-2V)

We move all terms to the left:

(V)-((11+-2V)(17+-2V))=0

We add all the numbers together, and all the variables

V-((-2V)(-2V))=0

We multiply parentheses ..

-((+4V^2))+V=0


We calculate terms in parentheses: -((+4V^2)), so:

(+4V^2)

We get rid of parentheses

4V^2

Back to the equation:

-(4V^2)


a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8}
=1/4
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8}
=0
$