U-2/u-3=u-2/u+1+1

Solution for U-2/u-3=u-2/u+1+1 equation:

-2/U-3=U-2/U+1+1

We move all terms to the left:

-2/U-3-(U-2/U+1+1)=0


Domain of the equation: U!=0

U∈R



Domain of the equation: U+1+1)!=0

We move all terms containing U to the left, all other terms to the right

U+1)!=-1

U∈R


We add all the numbers together, and all the variables

-2/U-(U-2/U+2)-3=0

We get rid of parentheses

-2/U-U+2/U-2-3=0

We multiply all the terms by the denominator


-U*U-2*U-3*U-2+2=0

We add all the numbers together, and all the variables

-5U-U*U=0

Wy multiply elements

-1U^2-5U=0

a = -1; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-1)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$U_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$U_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$U_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-1}=\frac{0}{-2}
=0
$
$U_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-1}=\frac{10}{-2}
=-5
$