T=-16t2+20t+6

Solution for T=-16t2+20t+6 equation:

=-16T^2+20T+6

We move all terms to the left:

-(-16T^2+20T+6)=0

We get rid of parentheses

16T^2-20T-6=0

a = 16; b = -20; c = -6;
Δ = b2-4ac
Δ = -202-4·16·(-6)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*16}=\frac{-8}{32}
=-1/4
$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*16}=\frac{48}{32}
=1+1/2
$