T/12(y+5)=13y+2

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Solution for T/12(y+5)=13y+2 equation: 



/12(T+5)=13T+2

We move all terms to the left:

/12(T+5)-(13T+2)=0



Domain of the equation: 12(T+5)!=0

T∈R



We get rid of parentheses

/12(T+5)-13T-2=0

We multiply all the terms by the denominator


-13T*12(T+5)-2*12(T+5)+=0

We add all the numbers together, and all the variables

-13T*12(T+5)-2*12(T+5)=0

Wy multiply elements

-156T^2(T-24T(T=0

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