Sqrt(7+x)+sqrt(2x-3)=4

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Solution for Sqrt(7+x)+sqrt(2x-3)=4 equation: 


Simplifying
Sqrt(7 + x) + sqrt(2x + -3) = 4
(7 * qrtS + x * qrtS) + sqrt(2x + -3) = 4
(7qrtS + qrtxS) + sqrt(2x + -3) = 4

Reorder the terms:
7qrtS + qrtxS + qrst(-3 + 2x) = 4
7qrtS + qrtxS + (-3 * qrst + 2x * qrst) = 4
7qrtS + qrtxS + (-3qrst + 2qrstx) = 4

Reorder the terms:
-3qrst + 2qrstx + 7qrtS + qrtxS = 4

Solving
-3qrst + 2qrstx + 7qrtS + qrtxS = 4

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
-4 + -3qrst + 2qrstx + 7qrtS + qrtxS = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + -3qrst + 2qrstx + 7qrtS + qrtxS = 0

The solution to this equation could not be determined.

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