Sin(5x-40)=cos(2x-10)

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Solution for Sin(5x-40)=cos(2x-10) equation:


Simplifying
Sin(5x + -40) = cos(2x + -10)

Reorder the terms:
inS(-40 + 5x) = cos(2x + -10)
(-40 * inS + 5x * inS) = cos(2x + -10)
(-40inS + 5inxS) = cos(2x + -10)

Reorder the terms:
-40inS + 5inxS = cos(-10 + 2x)
-40inS + 5inxS = (-10 * cos + 2x * cos)
-40inS + 5inxS = (-10cos + 2cosx)

Solving
-40inS + 5inxS = -10cos + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
10cos + -2cosx + -40inS + 5inxS = -10cos + 2cosx + 10cos + -2cosx

Reorder the terms:
10cos + -2cosx + -40inS + 5inxS = -10cos + 10cos + 2cosx + -2cosx

Combine like terms: -10cos + 10cos = 0
10cos + -2cosx + -40inS + 5inxS = 0 + 2cosx + -2cosx
10cos + -2cosx + -40inS + 5inxS = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
10cos + -2cosx + -40inS + 5inxS = 0

The solution to this equation could not be determined.

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