Sin(4x-7)=cos(2x+23)

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Solution for Sin(4x-7)=cos(2x+23) equation: 


Simplifying
Sin(4x + -7) = cos(2x + 23)

Reorder the terms:
inS(-7 + 4x) = cos(2x + 23)
(-7 * inS + 4x * inS) = cos(2x + 23)
(-7inS + 4inxS) = cos(2x + 23)

Reorder the terms:
-7inS + 4inxS = cos(23 + 2x)
-7inS + 4inxS = (23 * cos + 2x * cos)
-7inS + 4inxS = (23cos + 2cosx)

Solving
-7inS + 4inxS = 23cos + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-23cos + -2cosx + -7inS + 4inxS = 23cos + 2cosx + -23cos + -2cosx

Reorder the terms:
-23cos + -2cosx + -7inS + 4inxS = 23cos + -23cos + 2cosx + -2cosx

Combine like terms: 23cos + -23cos = 0
-23cos + -2cosx + -7inS + 4inxS = 0 + 2cosx + -2cosx
-23cos + -2cosx + -7inS + 4inxS = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
-23cos + -2cosx + -7inS + 4inxS = 0

The solution to this equation could not be determined.

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