Sin(4x-10)=cos(7x-21)

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Solution for Sin(4x-10)=cos(7x-21) equation:


Simplifying
Sin(4x + -10) = cos(7x + -21)

Reorder the terms:
inS(-10 + 4x) = cos(7x + -21)
(-10 * inS + 4x * inS) = cos(7x + -21)
(-10inS + 4inxS) = cos(7x + -21)

Reorder the terms:
-10inS + 4inxS = cos(-21 + 7x)
-10inS + 4inxS = (-21 * cos + 7x * cos)
-10inS + 4inxS = (-21cos + 7cosx)

Solving
-10inS + 4inxS = -21cos + 7cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
21cos + -7cosx + -10inS + 4inxS = -21cos + 7cosx + 21cos + -7cosx

Reorder the terms:
21cos + -7cosx + -10inS + 4inxS = -21cos + 21cos + 7cosx + -7cosx

Combine like terms: -21cos + 21cos = 0
21cos + -7cosx + -10inS + 4inxS = 0 + 7cosx + -7cosx
21cos + -7cosx + -10inS + 4inxS = 7cosx + -7cosx

Combine like terms: 7cosx + -7cosx = 0
21cos + -7cosx + -10inS + 4inxS = 0

The solution to this equation could not be determined.

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