Sin(4x)-3cos(2x)=4

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Solution for Sin(4x)-3cos(2x)=4 equation: 


Simplifying
Sin(4x) + -3cos(2x) = 4

Remove parenthesis around (4x)
inS * 4x + -3cos(2x) = 4

Reorder the terms for easier multiplication:
4inS * x + -3cos(2x) = 4

Multiply inS * x
4inxS + -3cos(2x) = 4

Remove parenthesis around (2x)
4inxS + -3cos * 2x = 4

Reorder the terms for easier multiplication:
4inxS + -3 * 2cos * x = 4

Multiply -3 * 2
4inxS + -6cos * x = 4

Multiply cos * x
4inxS + -6cosx = 4

Reorder the terms:
-6cosx + 4inxS = 4

Solving
-6cosx + 4inxS = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4inxS' to each side of the equation.
-6cosx + 4inxS + -4inxS = 4 + -4inxS

Combine like terms: 4inxS + -4inxS = 0
-6cosx + 0 = 4 + -4inxS
-6cosx = 4 + -4inxS

Divide each side by '-6osx'.
c = -0.6666666667o-1s-1x-1 + 0.6666666667ino-1s-1S

Simplifying
c = -0.6666666667o-1s-1x-1 + 0.6666666667ino-1s-1S

Reorder the terms:
c = 0.6666666667ino-1s-1S + -0.6666666667o-1s-1x-1

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