Sin(3x-10)=cos(x-10)

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Solution for Sin(3x-10)=cos(x-10) equation:


Simplifying
Sin(3x + -10) = cos(x + -10)

Reorder the terms:
inS(-10 + 3x) = cos(x + -10)
(-10 * inS + 3x * inS) = cos(x + -10)
(-10inS + 3inxS) = cos(x + -10)

Reorder the terms:
-10inS + 3inxS = cos(-10 + x)
-10inS + 3inxS = (-10 * cos + x * cos)
-10inS + 3inxS = (-10cos + cosx)

Solving
-10inS + 3inxS = -10cos + cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
10cos + -1cosx + -10inS + 3inxS = -10cos + cosx + 10cos + -1cosx

Reorder the terms:
10cos + -1cosx + -10inS + 3inxS = -10cos + 10cos + cosx + -1cosx

Combine like terms: -10cos + 10cos = 0
10cos + -1cosx + -10inS + 3inxS = 0 + cosx + -1cosx
10cos + -1cosx + -10inS + 3inxS = cosx + -1cosx

Combine like terms: cosx + -1cosx = 0
10cos + -1cosx + -10inS + 3inxS = 0

The solution to this equation could not be determined.

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