Sin(3x-10)=cos(5x+20)

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Solution for Sin(3x-10)=cos(5x+20) equation:


Simplifying
Sin(3x + -10) = cos(5x + 20)

Reorder the terms:
inS(-10 + 3x) = cos(5x + 20)
(-10 * inS + 3x * inS) = cos(5x + 20)
(-10inS + 3inxS) = cos(5x + 20)

Reorder the terms:
-10inS + 3inxS = cos(20 + 5x)
-10inS + 3inxS = (20 * cos + 5x * cos)
-10inS + 3inxS = (20cos + 5cosx)

Solving
-10inS + 3inxS = 20cos + 5cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-20cos + -5cosx + -10inS + 3inxS = 20cos + 5cosx + -20cos + -5cosx

Reorder the terms:
-20cos + -5cosx + -10inS + 3inxS = 20cos + -20cos + 5cosx + -5cosx

Combine like terms: 20cos + -20cos = 0
-20cos + -5cosx + -10inS + 3inxS = 0 + 5cosx + -5cosx
-20cos + -5cosx + -10inS + 3inxS = 5cosx + -5cosx

Combine like terms: 5cosx + -5cosx = 0
-20cos + -5cosx + -10inS + 3inxS = 0

The solution to this equation could not be determined.

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