Sin(2x-10)=cos(3x+5)

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Solution for Sin(2x-10)=cos(3x+5) equation: 


Simplifying
Sin(2x + -10) = cos(3x + 5)

Reorder the terms:
inS(-10 + 2x) = cos(3x + 5)
(-10 * inS + 2x * inS) = cos(3x + 5)
(-10inS + 2inxS) = cos(3x + 5)

Reorder the terms:
-10inS + 2inxS = cos(5 + 3x)
-10inS + 2inxS = (5 * cos + 3x * cos)
-10inS + 2inxS = (5cos + 3cosx)

Solving
-10inS + 2inxS = 5cos + 3cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-5cos + -3cosx + -10inS + 2inxS = 5cos + 3cosx + -5cos + -3cosx

Reorder the terms:
-5cos + -3cosx + -10inS + 2inxS = 5cos + -5cos + 3cosx + -3cosx

Combine like terms: 5cos + -5cos = 0
-5cos + -3cosx + -10inS + 2inxS = 0 + 3cosx + -3cosx
-5cos + -3cosx + -10inS + 2inxS = 3cosx + -3cosx

Combine like terms: 3cosx + -3cosx = 0
-5cos + -3cosx + -10inS + 2inxS = 0

The solution to this equation could not be determined.

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