Sin(2x+30)=cos(3x+40)

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Solution for Sin(2x+30)=cos(3x+40) equation:


Simplifying
Sin(2x + 30) = cos(3x + 40)

Reorder the terms:
inS(30 + 2x) = cos(3x + 40)
(30 * inS + 2x * inS) = cos(3x + 40)
(30inS + 2inxS) = cos(3x + 40)

Reorder the terms:
30inS + 2inxS = cos(40 + 3x)
30inS + 2inxS = (40 * cos + 3x * cos)
30inS + 2inxS = (40cos + 3cosx)

Solving
30inS + 2inxS = 40cos + 3cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-40cos + -3cosx + 30inS + 2inxS = 40cos + 3cosx + -40cos + -3cosx

Reorder the terms:
-40cos + -3cosx + 30inS + 2inxS = 40cos + -40cos + 3cosx + -3cosx

Combine like terms: 40cos + -40cos = 0
-40cos + -3cosx + 30inS + 2inxS = 0 + 3cosx + -3cosx
-40cos + -3cosx + 30inS + 2inxS = 3cosx + -3cosx

Combine like terms: 3cosx + -3cosx = 0
-40cos + -3cosx + 30inS + 2inxS = 0

The solution to this equation could not be determined.

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