Sin(10-3x)=cos(2x-60)

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Solution for Sin(10-3x)=cos(2x-60) equation: 


Simplifying
Sin(10 + -3x) = cos(2x + -60)
(10 * inS + -3x * inS) = cos(2x + -60)
(10inS + -3inxS) = cos(2x + -60)

Reorder the terms:
10inS + -3inxS = cos(-60 + 2x)
10inS + -3inxS = (-60 * cos + 2x * cos)
10inS + -3inxS = (-60cos + 2cosx)

Solving
10inS + -3inxS = -60cos + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
60cos + -2cosx + 10inS + -3inxS = -60cos + 2cosx + 60cos + -2cosx

Reorder the terms:
60cos + -2cosx + 10inS + -3inxS = -60cos + 60cos + 2cosx + -2cosx

Combine like terms: -60cos + 60cos = 0
60cos + -2cosx + 10inS + -3inxS = 0 + 2cosx + -2cosx
60cos + -2cosx + 10inS + -3inxS = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
60cos + -2cosx + 10inS + -3inxS = 0

The solution to this equation could not be determined.

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