S=8+3(-s-12)

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Solution for S=8+3(-s-12) equation: 



=8+3(-S-12)

We move all terms to the left:

-(8+3(-S-12))=0

We add all the numbers together, and all the variables

-(8+3(-1S-12))=0



We calculate terms in parentheses: -(8+3(-1S-12)), so:

8+3(-1S-12)

determiningTheFunctionDomain
3(-1S-12)+8

We multiply parentheses

-3S-36+8

We add all the numbers together, and all the variables

-3S-28

Back to the equation:

-(-3S-28)



We get rid of parentheses

3S+28=0

We move all terms containing S to the left, all other terms to the right

3S=-28

S=-28/3

S=-9+1/3

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