S=4(n-1)+6

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Solution for S=4(n-1)+6 equation: 



=4(S-1)+6

We move all terms to the left:

-(4(S-1)+6)=0



We calculate terms in parentheses: -(4(S-1)+6), so:

4(S-1)+6

We multiply parentheses

4S-4+6

We add all the numbers together, and all the variables

4S+2

Back to the equation:

-(4S+2)



We get rid of parentheses

-4S-2=0

We move all terms containing S to the left, all other terms to the right

-4S=2

S=2/-4

S=-1/2

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