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+31/2S+10S=46
We move all terms to the left:
+31/2S+10S-(46)=0
Domain of the equation: 2S!=0We add all the numbers together, and all the variables
S!=0/2
S!=0
S∈R
10S+31/2S-46=0
We multiply all the terms by the denominator
10S*2S-46*2S+31=0
Wy multiply elements
20S^2-92S+31=0
a = 20; b = -92; c = +31;
Δ = b2-4ac
Δ = -922-4·20·31
Δ = 5984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5984}=\sqrt{16*374}=\sqrt{16}*\sqrt{374}=4\sqrt{374}$$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-4\sqrt{374}}{2*20}=\frac{92-4\sqrt{374}}{40} $$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+4\sqrt{374}}{2*20}=\frac{92+4\sqrt{374}}{40} $
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